12x^2+144x-1296=0

Solution for 12x^2+144x-1296=0 equation:

12x^2+144x-1296=0

a = 12; b = 144; c = -1296;
Δ = b2-4ac
Δ = 1442-4·12·(-1296)
Δ = 82944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{82944}=288$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(144)-288}{2*12}=\frac{-432}{24}
=-18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(144)+288}{2*12}=\frac{144}{24}
=6
$